A generator with a 6% droop governor is connected to a 60 HZ power system, initially at 100% load. If the frequency falls by 0.9 HZ, what is the new percentage output of the generator?

To understand how to calculate the new percentage output of the generator based on the 6% droop governor setting, we need to delve into the concept of droop and its impact on generator output in relation to frequency changes.

Droop is a method used in generator control to maintain frequency stability in a power system. The droop percentage indicates how much the generator’s output power will change in response to a change in system frequency. For a generator with a 6% droop, when the system frequency decreases, the output of the generator will also reduce.

In this scenario, the power system operates at a nominal frequency of 60 Hz. A droop of 6% means that for a drop of 6% of the nominal frequency, the generator will reduce its output by 100%. The 6% of 60 Hz is calculated as follows:

(6% \text{ of } 60 \text{ Hz} = 0.06 \times 60 = 3.6 \text{ Hz}.)

When the frequency drops by 0.9 Hz, we can express this drop in relation to the full range of 3.6 Hz. The percentage drop can be calculated as:

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